Question

The sum of two digit number and the number obtained by reversing its digit is 143. Find the number if its ten place digit is greater than the unit place digit by 3.​

Answer 1

Answer:

it should be 143 =39

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Answer 2

Answer:

let 10 th place unit is x and ones place number is y

so given x = y + 3

also 10x + y + 10y + x = 143

11x + 11 y = 143

11 ( x + y ) = 143

x + y = 13

y + 3 + y = 13

2y = 10

y = 5

so x = 5 + 3 = 8

so number is 85