Question

The sum of two digit number and the number obtained by reversing the digits is 121.

The digit at tens place is 7 more than the digit at unit place. Find the number.​

Answer 1

Answer:

29

Step-by-step explanation:

Let the unit place digit of the two digit number is y and the tens place digit is x

The number is 10x+y

The number obtained by reversing the digit is 10y+x

A.T.Q

(10x+y)+(10y+x)= 121

11x+11y=121                                              ∴ x+y= 11    (1)

Also, x=y+7                                             ∴ x-y= 7     (2)

Adding (1) and (2), 2x= 18   x= 9

from (1) a+y= 11  y=2

the two digit number is 29.