Question

the sum of two digit number and the number obtained by reversing the digit is 121 the digit at tens place is 7 more than the digit at unit place find the number.
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Answer 1

Answer:

Thus Number=92

Step-by-step explanation:

Let the digit at unit place=x

then at 10's place=x+7

Then No  N =10(x+7)+x=11x+70

Now the number formed by reversing didits

N'=10x+(x+7)=11x+7

Given that

N+N'=121

11x+70+11x+7=121

22x=121-77=44

x=2

So Unit digits=2

10's digits=2+7=9

Thus Number=92

Answer 2

Hope this will help you.

Please refer this image.

And Extremely Sorry if my handwriting is bad.