Question

The sum of two digit number and the number obtained by reversing its digit is 121.Find the number if its unit place is 5

Answer 1

Answer:

65

65+56

let no.be to

reverse will be 5t

t*10+5+5*10+t=11t+55=121=11t=66=t=6

so no.=65

Answer 2

Let the unit digit is ‘x’ and the 10th digit is ‘y’

The number is 10 y +x

Reversed number is 10 x+y

Given 11 x+11 y =121`

x+y=11 [dividing by 11]…….1

Also x-y=3 ……2

solving 1 and 2 we get

x=7 and y=4

The number is 47 [check 47+74=121, 7–4=3]