the sum of two digit number and the number obtained by reversing the digits is 66.if the digits of the number differ by 2,find the number .how many such numbers are there
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heya!! your answer is 42
let the small digit be x
then ,
10(x)+1(x+2)+10(x+2)+1(x)=66
11x+2+11x+20
22x+22
22x=66-22=44
x=2
then the no
is 42
let the small digit be x
then ,
10(x)+1(x+2)+10(x+2)+1(x)=66
11x+2+11x+20
22x+22
22x=66-22=44
x=2
then the no
is 42
sai725:
i dont want answer with proof
oh
wait i am editing
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