The sum of two digit number and the number obtained by reversing the order of its digits is 165. if the digit differ by 3 find the number?
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let the no. on units place be x
no. on tens place be y
=10y+x
A.T.Q.
x-y=3
x+3=y
and on reversing it will be 10x+y
10y+x+10x+y=165
11y+11x=165
11(x+3)+11x=165 put value of y=x+3
on solving , we get
22x = 165-33
22x= 132
x=6
we have
x+3=y
y=6+3
y=9
two digit no is 69
on reversing you will get 96
69+96=165
no. on tens place be y
=10y+x
A.T.Q.
x-y=3
x+3=y
and on reversing it will be 10x+y
10y+x+10x+y=165
11y+11x=165
11(x+3)+11x=165 put value of y=x+3
on solving , we get
22x = 165-33
22x= 132
x=6
we have
x+3=y
y=6+3
y=9
two digit no is 69
on reversing you will get 96
69+96=165
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