Question

The sum of two digit number and the number obtained by reversing the order of its digits is 121 and the two digits differ by 3
Find the number

Answer 1

Let the unit digit is ‘x’ and the 10th digit is ‘y’

The no is 10y+x

Reversed no is 10x+y

Given 11x+11y=121

Therefore x+y=11

Now x-y=3 as given in question therefore on solving it you get

X=7 and Y=4 so the no are 47 and 74

Answer 2

Refers to attachment !!