The sum of two digit number and the number obtained by reversing the order of its digits is 121 and the two digits differ by 3
Find the number
Answers
Answered by
12
Let the unit digit is ‘x’ and the 10th digit is ‘y’
The no is 10y+x
Reversed no is 10x+y
Given 11x+11y=121
Therefore x+y=11
Now x-y=3 as given in question therefore on solving it you get
X=7 and Y=4 so the no are 47 and 74
Answered by
68
Refers to attachment !!
Attachments:
Similar questions