The sum of two digit number and the number obtained on reversing the digits is 165.If the digits differ by 3,find the numbers?
Answers
Step-by-step explanation:
Given that:
Sum of 2 digit number and number obtained by reversing is = 165
The digits differ by 3
and also ten’s digit is bigger than unit’s digit
Let the digits of the number be x and y
So by applying the given conditions we get the following equations:
(10x+y)+(10y+x)=165 ————–(i)
x-y=3 ——————-(ii)
11x+11y=165
Taking out 11 as a common factor
x+y=15 ———————-(iii)
Solving (ii) and (iii) we get,
2x=18
x=9
y=15–9=6
Hence the number is 96
Verification:
We can verify by substituting the values in the given conditions:
96 + 69 = 165
9-6=3
Hence both the conditions are verified.
96 is the required number.
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Answer:
96 or 69
Step-by-step explanation:
Let the digits be x and y
Given,
x-y = 3 ---(1) / y-x = 3 ---(2)
and
(10x + y) + (10y + x ) = 165
11x + 11 y = 165
x+ y = 15 ---(3)
Adding (1)&(3) Adding (2) &(3)
we get we get
x= 9 x= 6
y= 6 y= 9
so the number could be either 96 or 69
I hope my explanation will help you with your query