the sum of two digit number is 10 if formed by interchanging the digits is less than the original number by 36 find the original number
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let no.be 10x+y...
and x+y=10..eq(1)
acc..to que. .(10x+y)-(10y+x)=36
so 9(x-y)=36
so x-y=4...eq(2)..
by adding eq. 1 and 2 we got
x=7
and y=3
original no=73
and x+y=10..eq(1)
acc..to que. .(10x+y)-(10y+x)=36
so 9(x-y)=36
so x-y=4...eq(2)..
by adding eq. 1 and 2 we got
x=7
and y=3
original no=73
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