Question

the sum of two digit number is 10. square of tens digit is divided by cube of ones digit is equal to the tens digit. find the number

Answer 1

Answer:

Step-by-step explanation:

Let the number is JK

The number is 28

K^2/J^3 = 8^2/2^3 = 64/8 = 8

Sum of two numbers = 2 +8 = 10

HENCE THE NUMBER IS 28

Answer 2

The number is 82

Step-by-step explanation:

Let the ones place digit and ten's place digit be x and y

So, the sum of two digit number is 10.

x+y=10 ---1

Square of tens digit is divided by cube of ones digit is equal to the tens digit

$\frac{y^2}{x^3}=y$

$y=x^3$

Substitute the value of y in 1

$x+x^3=10$

$x^3+x-10=0$

$(x-2)(x^2+2x+5)=0$

$x=2$

So, y=10-x=10-2=8

The number is 82

#Learn more:

The sum of the digits of a two digit number is 10 if 18 is added to the number it's digits are reversed. Find the number ​

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