the sum of two digit number is 11.if it's reversed ,the new number so formed is 9 less than then the original number. find the original number
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answer is 65
Step-by-step explanation:
let two digit no is AB,
Ab=10*A+1*b,
=10A+B
if it is reversed ,
10A+B = 10B+A,
ATQ, new number is formed is 9 less then the original number,
(10A+B) = (10B+A)+9,
9A - 9B = 9,
A-B = 1
A+B = 11,
A-b+A+b = 1+11,
2A = 12
A = 6
b = 11 - 6 = 5
10A+B
10*6+5
60+5
=65
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