Question

the sum of two digit number is 12. if the new number formed by reversing the digits is greter than the original number is 18 . find the original number .

Answer 1

hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝ ☝☝☝☝☝☝☝☝☝☝☝☝☝ ☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝


Let to be 10' digit number be x
Let to be 1 unit digit be y

then,
A/q

x+y=12. ----;-(1)




Again,

10x+y+18=10y+x

10x-x-10y+y=-18

9x-9y=-18

9(x-y)=-18

x-y=-2


then,


Solving the equation by elimination method,


x+y=12

x-y=-2


______
2y=14

y=14/2

y=7


then,

x+y=12

x+7=12
x=12-7
x=5



that's
means



original number=10x+y

10*5+7
50+7
57


that's all

Answer 2

Let the tens place digit be x and unit place be y
sum of two digits = x+y=12 .....(i)
Original Number =10x+y
According to the question
10x+y+18 =10y+x
10x-x-10y+y =-18
9x-9y = -18
x-y= -2 .....(ii)
add equation (i) and (ii) , we get
2x=10
x = 10/2
x= 5
substitute the value of x = 5 in equation (i)
5+y =12
y =12-5
y = 7
Original number =57