The sum of two digit number is 12.if the new number formed by reversing the digit is greater than the orginal number by 54find the orginal number
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let unit place be. x
------ ten's place be. y
the number is 10y+x
the reverse number is 10x+y
case. 1
x+y=12. (1)
case. 2
10x+y=(10y+x)+54
10x+y-10y-x=54
9x-9y=54
9(x-y)=54
x-y=6. (2)
from eq. 1 & 2
x+y=12
x-y=6
2x=18. x=9
put the value of x in eq 1
x+y=12
9+y=12. y=3
The number is 10y+x
=10*3+9
=39
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