The sum of two digit number is 12 the number obtained interchanging its exceed the given number by 18 find the number
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lets the two digit number be x and y where x in 10 place and y in once ( 10x + y )
ATQ
•CASE 1 : the sum of two digit is 12
x + y = 12-----(1)
•CASE 2: the no. obtained interchanging its exceed the given no. (10x + y ) by 18
10y + x = 10x +y + 18
9y-9x = 18
9 (-x+y) = 18
-x + y = 2-----(2)
on adding 1 and 2
you will get value
ATQ
•CASE 1 : the sum of two digit is 12
x + y = 12-----(1)
•CASE 2: the no. obtained interchanging its exceed the given no. (10x + y ) by 18
10y + x = 10x +y + 18
9y-9x = 18
9 (-x+y) = 18
-x + y = 2-----(2)
on adding 1 and 2
you will get value
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