the sum of two digit number is 12 the number obtained by reversing the order of the digit of the given number exceeded by the given number by 18 find the two digit number
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let two no. be x and y.
original no.=10y+x
and, x+y=12 ..... (1)
Now by reversing the order
10x+y+18=10y +x
9x-9y=-18 ..... (2)
multiplying (1) by 9
9x+9y=108 ..... (3)
adding (2) and (3)
9x+9y+9x-9y=-18+108
18x=90
x=5
so by solving (1)
y=7
so original no. 10y+x
10 (7)+5=70+5=75
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