The sum of two digit number is 15. If the number formed by the reversing the digits is less then the original number by 27, then find the original number.
Answers
Answered by
2
Answer:
96
Step-by-step explanation:
let tens digit of the original number be x
so original number,
10(x) + (15-x)
reversing digits mean
10(15-x) + x
therefore
[10(x) + (15-x)]-[10(15-x)+x] = 27
or 10x + 15-x - 150+10x-x = 27
or 10x + 10x + 15 - 150 -x - x = 27
or 20x - 135 -2x = 27
or 18x - 135 = 27
or 18x = 27 + 135
or 18x = 162
or x = 162/18
or x = 9
original number = 10(x) + (15-x)
= 10(9) + (15-9)
= 90+6
= 96
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Answered by
1
Answer:
Step-by-step explanation:
X+y=15
10x+y-(10y+x)=27
9x-9y=27
9(x-y)=27
X-y=3
X=15-y
15-y-y=3
-2y=-12
Y=6
X=15-6
=9
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