Question

The sum of two digit number is 15. If the number formed by the reversing the digits is less then the original number by 27, then find the original number.

Answer 1

Answer:

96

Step-by-step explanation:

let tens digit of the original number be x

so original number,

10(x) + (15-x) 

reversing digits mean

10(15-x) + x

therefore

[10(x) + (15-x)]-[10(15-x)+x] = 27

or  10x + 15-x - 150+10x-x = 27

or 10x + 10x + 15 - 150 -x - x = 27

or 20x - 135 -2x = 27

or 18x - 135 = 27

or 18x = 27 + 135

or 18x = 162

or x = 162/18

or x = 9

original number = 10(x) + (15-x) 

                             = 10(9) + (15-9)

                             = 90+6

                             = 96

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Answer 2

Answer:

Step-by-step explanation:

X+y=15

10x+y-(10y+x)=27

9x-9y=27

9(x-y)=27

X-y=3

X=15-y

15-y-y=3

-2y=-12

Y=6

X=15-6

=9