Question

the sum of two digit number is 15 the number obtained by reversing the order of digits of the given number exceeds the number by 9 find the number

Answer 1

x+y=15 -eq 1
10y+x=10x+y+9
9y-9x=9
y-x=1 -eq 2

x + y = 15
-x + y = 1
2y = 16
y=8
put value of y in eq 1
x+8=15
x=15-8
x=7
Given No. = 87

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Answer 2

here is your answer.....
Let to be the one digits no x
required no y...
so,,
x+y=15
no. obtained on reversing the digit.
(10y+x)-(10x+y)=9
10y+x-10x-y=9
9y-9x=9
9(y-x)=9
y-x=1

by elimination method for solving
x+y=15
-x+y=1
----------
2y=16
y=8

put the value of y in another equation..
x+y=15
x+8=15
x=15-8
x=7
then.
required no be =(10x+y)
10*7+8
70+8
78------++ answer