Question

The sum of two digit number is 17. If the number formed by reversing the digits is less than the original number by 9,find the original number..​

Answer 1

SOLUTION ::

Let unit place = b, ten place = a

So the number is 10a+b

Now by the given condition

a+b=17 - - - - - - - - (1)

when number’s digits are reversed then resulting number is 10b + a

Since the number formed by reversing the digits is less than the original number by 9

(10a + b) - ( 10b +a) =9

➙ 9a - 9b = 9

➙ a - b = 1 - - - - - - - (2)

Adding Equation (1) & Equation (2)

2a = 18

➙ a = 9

From Equation (1)

b = 17 - 9 = 8

So the original number is = (10×9) +8 = 98

Answer 2

Answer:

★FIND:

the original number = ?

★GIVEN,

The sum of two digit number is 17.

If the number formed by reversing the digits is less than the original number by 9.

★SOLUTION:

The sum of two digit number is 17

➡️8+9=17

➡️9+8=17

So the 8+9=17 is correct.

if we reverse 89 then we get 98.

Subtract 9 from the reversed number 98

=>98-9

=>89

The original number is 98.