Question

The sum of two digit number is 7 the number formed by reversing the digits is less than the original number by 9 find the number

Answer 1

$\bf{\huge{Answer}}$

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Let to be 10'digit Number=x

Let to be 1 unit digit number=y

ACCORDING TO THE QUESTION;

$\huge{\fbox{\color{\green}{X+Y=7}}}}$

10x+y-9=10y+x

10x-x+y-10y=9

9x-9y=9

9(x-y)=9

x-y=1(II ND Equation)

Now solving the equation 1 and 2:-

x+y=7

x-y=1

________
2y=6

y=6/2

y=3

Again Putting the value of the required terms;

x+y=7

x+3=7

x=7-3

X=4

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REQUIRED ANSWER=10Y+X

10(4)+3

40+3

43
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THANKS!!!!!!!!!!!