the sum of two digit number is 8 if the digit of the number are reversed the number remain the same find the number
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let ones digit = x
tens digit = 10 y
10 y+x =8
digits are reversed
= 10x +y= 8
10y+ x -8 = 10x + y
tens digit = 10 y
10 y+x =8
digits are reversed
= 10x +y= 8
10y+ x -8 = 10x + y
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