Question

THE SUM OF TWO DIGIT NUMBER IS 9 ALSO 9 TIMES THIS NUMBER IS TWICE THE NUMBER OBTAINED THE REVERSED FIND THE TWO DIGIT NUMBER

Answer 1

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Answer 2

Answer:

Let the units digit be x and tens digit be 9-x

Original no.=10(9-x)+x=90-9x

no. formed after reversing the digits=10x+9-x=9x+9

According to question,

9(90-9x)=2(9x+9)

810-81x=18x+18

810-18=18x+81x

792=99x

x=792/99=8

therefore the no.=10(9-8)+8=18