Question

the sum of two digit number is 9 the number obtained by interchanging the digit exceeds the given number by 27 the number is​

Answer 1

Let the two digit number be 10x + y

Given that the sum of the digits is 9

x + y = 9 (equation 1)

Given that the number obtained by interchanging the digits exceeds the given number by 27

10y + x = 10x + y + 27 

9x - 9y = - 27

taking 9 as common

x - y = - 3 (equation 2)

Adding equation 1 and 2

x + y = 9

x - y = - 3

2x = 6

x = 3

3 + y = 9

y = 6

The number is 10x + y is 36.

Answer 2

Answer:

unit place be x.

and ten place be y.

Step-by-step explanation:

according to first condotion. x+y=9. according to 2nd condotion 9x-9y=27.(divide by 9) x-y=3. add two equations. x +y=9+x-y=3 ans is 2x=12 then x=2/12 x=6. put x in equation 1. x+y9. 6+y=9. y= 9-6 y=3