Question

the sum of two digit number is 9, the number obtained by interchanging the digit exceeds the given number by 27.find the given number​

Answer 1

Answer:

72

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Let the unit digit be x and the tens digit be y

Then the original number will be 10y + x

The number obtained by interchanging its digits will be 10x + y

A/q,

=» X+Y = 9 — (i)

=» (10y+x) +27 =10x+y

=» 10x - x - 10y + y =27

=» 9x - 9y = 27

=» 9(x - y) =27

=» x - y = 27÷9

=» x - y = 3 — (ii)

from equation 1 and 2

=» (x + y )+ (x - y )= 9 + 3

=» 2x = 12

=» x =12÷2

=» x = 6 — (iii)

putting the value of x in ( i ),we get

=» x + y = 9

=» 6 + y = 9

=» y = 9 - 6

=» y = 3

The original number will be

=» 10y + x

=» 10 × 3 + 6 × 1

=» 30 + 6

=» 36

The number obtained by interchanging its digits will be

=» 10x + y

=» 10 × 6 + 3 × 1

=» 60 + 3

=» 63