Question

The sum of two digit number is obtained either multiplying sum of the digit by8and adding 1 or by multiplying the difference of the digits by 8 13 and adding to find the number

Answer 1

Answer:

HOPE THE ANSWER GIVEN BELOW HELPS

Let the tense digit be x

And the units digit be y

The original equation is 10x+y

Acc. to first statement

10x+y=(x+y)×8+1

10x+y=8x+8y+1

10x-8x=8y-y+1

2x=7y+1......(i)

Acc to the second statement

10x+y=(x-y) ×13+2

10x+y=13x-13y+2

10x-13x=-y-13y+2

-3x=-14y+2

-3x+14y=2.....(ii)

Multiply equ I by 2 and add it with equ ii

4x-14y=2

-3x+14y=2

________

X=4

Now substitute the value of x in equ i

2(4)-7y=1

8-7y=1

8-1=7y

7=7y

Y=1

The original two digit no. =10x+y

=10(4)+1

=40+1=41

Step-by-step explanation: