Question

The sum of two digit numbre is 11 the nuber obtained by reversing the digit is 9 less than original number , find the number

Answer 1

Answer:

here your answer...........

65

Step-by-step explanation:

Let the ones place digit be y

and the tens place digit be x

Therefore the number is 10x + y

After reversing the number

we get = 10y + x

ATQ

sum of digits = 11

x + y = 11 ............(1)

and also

10y + x = 10x + y - 9

10y - y + x - 10x = -9

9y - 9x = -9

y - x = -1

x - y = 1..................(2)

Now

add equation (1) and equation (2)

we get

x+y+x-y=11+1

2x = 12

x = 6

put x value in equation (1)

6 + y = 11

y = 5

therefore the number is

10 x + y = 10 × 6 + 5 = 60 + 5 = 65.