The sum of two digits is 8. If 72 is subtracted from the number, the number is equal to the tens digit in the number. Find the number
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Answer:
Let a and b represent the two digits of the number.
From the question we know the following:
a + b = 10
(10a + b) - 72 = (10b + a)
The second equation can be rearranged as follows:
9a - 9b = 72
a - b = 8
We now have:
a + b = 10
a - b = 8
We can add these two equations together to get:
2a = 18
a = 9
Plugging that answer into second equation:
9 - b = 8
b = 1
So our original number is 91.
Here is another way to solve it. There are only three two-digit numbers larger than 72 whose digits add up to 10: 73, 82, and 91.
73 - 72 = 1
82 - 72 = 10
91 - 72 = 19
So our answer (again) is 91.
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