Question

The Sum Of Two Digits Is 9. Also , 9 times this number is twice the number obtained by reversing the order of the digits. Find the number.
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.Answer It Briefly On The Copy Or Sheet...​

Answer 1

Answer:

Let the ten's digit no. be x and one's digit no. be y.

So the no. will be = 10x+y.

Given : x+y=9-----(I)

9(10x+y)=2(10y+x) ⇒88x−11y=0 -----(II)

On solving I and II simultaneously you will get x=1 and y=8.

Therefore your desired no. is 18.