The sum of two digits number and the number obtained by interchanging the digits is 99. If the digit at tens place exceeds the digit at unit place by 3. Find the numbers.
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3
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Answered by
2
Answer:
63
Step-by-step explanation:
Let x be the number at units place and y be the number at tens place
Two digit number=10y + x
According to the conditions,
y=2x
2x-y=0..(1)
10x + y + 10y + x=99
11x + 11y=99
11(x + y)=99
x + y=99/11
x + y=9..(2)
Solving (1) and (2),we get
2x-y=0
x+y=9
3x=9
x=9/3
x=3
Putting x=3 in (1)
2x-y=0
2(3)-y=0
6-y=0
y=6
∴The two digit number=10y + x=10(6) + 3=63
∴The number is 63
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