Question

the sum of two digits numberd the number obtained by reversing its digit is 121

Answer 1

Step-by-step explanation:

Let the two digit number be 10x+y

On reversing its digits, we get the number 10y+x

Given, (10x+y)+(10y+x)=121

11x+11y=121

=> x+y=11 --- (1)

Given, x−y=3 -- (2)

Adding (1), (2), we get

2x=14 => x=7

Substituting

x=7 in the equation (2), we get 7−y=3=>y=4

Hence, the number is 74 or 47

Answer 2

Answer:

Given units digit is x and tens digit is y

Hence the two digit number = 10y + x

Number obtained by reversing the digits = 10x + y

Given that sum of a two digit number and the number obtained by reversing the order of its digits is 121.

Then (10y+x)+(10x+y)=121

⇒10y+x+10x+y=121

⇒11x+11y=121

⇒x+y=11

Thus the required linear equation is x + y = 11.