Question

The sum of two digits of a 2-digit number is 13. Reversing the digits increase the number by 27. What is the number?
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Answer 1

Answer:

the no is 58

Step-by-step explanation:

let the ones digit be x my friend

the the tens digit will be 13-x{since it is given that the sum of the digits is 13}

then the no is 10x+(13-x)

if the digits are reversed then the no is

10(13-x)+x{since the digits are reversed}

=130-10x+x=130-9x

9x+13+27=130-9x{since it is given that the no increases by 27}

try substituting this equation my friend ,then you will get the value of x=

18x=90

x=5

then the ones digit is x=5

tens digit=13-x=8

the no is 58

if you find my answer useful then mark my answer as brainliest

Answer 2

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✤ Required Answer:

✒️ GiveN:

• Sum of the two digits of a no. = 13
• Reversing increases thd no. by 27

✒️ To FinD:

• What is the original number......?

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✤ How to solve?

We will consider the two digits of the number any variable and then we will frame equations on the basis of provided conditions. Then, we can solve the simultaneous pair of linear equations to get the digits. Then, we can find the two digit number.

Any two digit number:

• ab = 10 × a + b

☃️ So, Let's solve the question...$.$

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✤ Solution:

Let,

• The digits be x and y

Then,

• Two digit number will be 10x + y

According to condition - 1),

➝ Sum of the digits = 13

➝ x + y = 13---------(1)

According to condition - 2),

• Two digit number = 10x + y
• Then, Reversed number = 10y + x

Given ATQ,

➝ Reversed number = Original + 27

➝ 10y + x = 10x + y + 27

➝ 10y + x - 10x - y = 27

➝ 9y - 9x = 27

➝ 9(y - x) = 27

➝ y - x = 3----------(2)

Adding eq.(1) and eq.(2),

➝ x + y + y - x = 13 + 3

➝ 2y = 16

➝ y = 8

Substituting y in eq.(1),

➝ x + 8 = 13

➝ x = 5

Then, The original number:

• 10x + y = 10 × 5 + 8 = 58

❄️ Hence, solved !!

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