Question

The sum of two digits of a 2-digit number is 13.The number formed by interchanging the digits is 45 more than the original number. Find the original number ​

Answer 1

Answer:

let the number be 10x+y

x+y=13

10x+y- 10y-x= 45

9x-9y=45

x-y=5

x=5+y

put the value of x in

x+y =13

5+y+y=13

2y=8

y=4, x=9

Answer 2

Answer:

let the original number be 10X+ y

Step-by-step explanation:

given :

1. the sum of digits of two digits number is = 13

2. the number formed by the interchange the digits is = +45 more than the number

To find: the original number

solution : let the no. be 10 x + y

X + y = 13

now . 10x + y - 10y- x =45

9x-9y= 45

X -Y = 5

now x= y+5

then.,

substitute x in x+y= 13

we get 5+y+y= 13

.... then 2y = 13 - 5 .

y = 4

we already got X = y+5. .. so X = 9

so the original number is 90+ 4

.... 94 is original number

so pleas mark brainliest answers