Question

the sum of two digits of a 2 digit number is 7. if the number formed by reversing the digits is more than the original number by 27. find the original number.

Answer 1

here's your solution dear...

Answer 2

Hey!


Let the Digit at ones place be x

Let the Digit at tens place be y

So , Number formed = x + 10y

Also, Number formed by reversing digits = y + 10x

According to the given question
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x + y = 7 --------------------------------------------------------(1)

x = 7 - y ----------------------------------------------------(2)

( x + 10 y )+ 27 . = ( y + 10 x )

x + 10 y + 27 - y - 10x = 0

9y - 9x + 27 = 0

9 ( y - x + 3 ) =0


y - x = -3

From (2) we have ,

y - ( 7 - y ) = -3

y - 7 + y = -3

2y - 7 = -3

2y = -3+7

2y= 4

y= 2

x =5


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⏪Number formed = x + 10y

= 5 + 10(2)

= 5 + 20

= 25


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