The sum of two digits of a number is 10.If 18 will be added in number,the digits are interchange.find out the number.
Answers
Answered by
0
Let the tens place digit be a
And unit place digit be b
According to first condition,
a + b = 10 -------(1)
According to second condition,
10a + b + 18 = 10b + a
=> 10a + b - 10b - a = - 18
=> 9a - 9b = - 18
=> a - b = - 2 ------(2)
On adding equation 1 and 2, we get
2a = 8
=> a = 4
Now,
On substituting the value of a in equation 1, we get
4 +b = 10
=> b = 6
Required number = 46
And unit place digit be b
According to first condition,
a + b = 10 -------(1)
According to second condition,
10a + b + 18 = 10b + a
=> 10a + b - 10b - a = - 18
=> 9a - 9b = - 18
=> a - b = - 2 ------(2)
On adding equation 1 and 2, we get
2a = 8
=> a = 4
Now,
On substituting the value of a in equation 1, we get
4 +b = 10
=> b = 6
Required number = 46
vedantkhadse2:
thank you
Answered by
0
27e7egdi865w 72766 387!@^×€73854 to 6277 6
Similar questions