Question

The sum of two digits of a two digit number is 12. If the digits are reversed, then the
number so formed exceeds the original number by 18. Find the original number.
is.​

Answer 1

Answer:

57

Step-by-step explanation:

let the digits are x and y.

so , x+y =12........(1)

now according to the second condition,

10x+y = 10y+x -18

=> 9x-9y = -18

=> x-y = -2 ........(2)

now,

(1)+(2)=> 2x=10 => x=5

(1)=> x+y =12 => y=7

therefore, original no is 10x+y = 57

Answer 2

Answer:

57

Step-by-step explanation:

Let th ones digit be x

Then. The tens digit=12-x

The number formed = 10×(12-x)+1×x

=120-10x+x

=120-9x

On reversing the digits, the new number formed =10×x+1×(12-x)

=10x+12-x

=9x+12

According to the given condition we have

New number= Original number +18

=9x+12=120-9x+18

9x+9x=138-12

18x=126

x=126/18=7

Then the tens digit =12-7=5

So th erequired number= 10×5+1×7 =57

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