Question

The sum of two digits of a two digits is 11 Reversing the digits increases the number by 45 . what is the number

Answer 1

Let the one's place digit be y
ten's place digit be x
Original no. = 10x+y
Reversed no. = 10y+x
Given,
x+y=11
x=11-y -(i)
10y+x -(10x+y) = 45
10y+x-10x-y = 45
9y-9x=45
9(y-x) = 45
y-x = 5
putting the value of x from eq.(i)
y-(11-y) =5
y-11+y = 5
2y = 5+11
2y = 16
y=8
Hence, x= 11-y
= 11-8
=3
Hence,
original no.=10x+y
=10*3+8
=38

Answer 2

Hey, mate here is you answer