Question

the sum of two digits of a two digits is 12 if 18 is added to it the digits are reversed find the number

Answer 1

Hey!

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Let the ones digit = x

Let the tens digit = y

Now

Sum of the digit

=> x + y = 12 (Equation 1)

Now

Number = 10y + x

Reserving digit = 10x + y

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Put in a equation

10x + y = 10y + x + 18

=> 10x - x - 10y + y = 18

=> 9x - 9y = 18

=> 9(x - y) = 18

=> x - y = 18 ÷ 9

=> x - y = 2 (Equation 2)

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Adding equation 1 and 2

2x = 12 + 2

2x = 14

x = 14 ÷ 2

x = 7

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Now put the value of x in equation 1

(7) + y = 12

=> y = 12 - 7

=> y = 5

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Put the value of

x = 5

y = 7

So the number is 57

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Answer 2

Hey! ! !

Solution :-

Let x be the one's digit and y be the ten's digit therefore number=10y+x

According to question,

X+Y=12….(1)

10y+x+18=10x+y

9y -9x=-18

Y-X=-2……(2)

(1)+(2)

2y=10

y=5

X=7

Therefore the number=57

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