Math, asked by archana883, 6 months ago

the sum of two digits of a two digits number is 7.on reversing the digits the number obtained is 27 more than the original number find the number. ​

Answers

Answered by yashsingh8704
0

Answer:

Step-by-step explanation:

let the units place be x

then the tens digit be 7 - x

number formed by these digits = 10 x t's digit+u's digit

=> 10(7-x)+x

70 x -10 x +x

70 x -9x

when the digits are interchanged than,

t's digit= x

u's digit = 7-x

the new no. formed = 10x + 7-x

= 9 x +7

given that the no. exceeds by 27

new no. - given no.

9x +7 - (70-9x)=27

9 x + 7 - 70 + 9x =27

18x -63= 27

18 x = 63+27

18 x= 90

x = 90/18

=5

the no. = 70- 9x

=> 70-45

=> 25 ans

Answered by sonampreet60dabda
1

Answer:

Suppose the two digit original number is 10x+y.

(x is at tens place so multiple by 10 and y is at unit place so left as is, you may multiply it by 1 to get a clear picture but 1y is represented as y only)

The sum of digits of original number is 7 →x+y = 7 —equation(1)

If 27 is added to original number its digits are interchanged .So, 10x + y +27 =10y+ x → 9x +27 = 9y → 9(x+3) = 9(y) → x+3 = y — equation(2)

Substituting value of y from equation (2) in equation (1)

x + x+3 = 7

2x + 3 = 7

2x =4

x= 2

Substituting x= 2 in equation (2)

y= 5

So original number is 10 (2) + 5 i.e. 20 +5 → 25.

In order to check the answer.. 25 is original number and 52 is the number formed by interchanging the digits.

25 +27 = 52.

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