the sum of two digits of is 7 if the new number formed by reversing the disit is greater than the original number by 27 then find the original number
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2
let the no. at 10's place be x
at 1's place be y
by 1st condition
x+y=7......(1)
10y+x=27+10x+y
9x-9y=27
x-y=3....(2)
Solving eq (1) and (2)
we get
x=5
y=2
Plz mark brainliest
at 1's place be y
by 1st condition
x+y=7......(1)
10y+x=27+10x+y
9x-9y=27
x-y=3....(2)
Solving eq (1) and (2)
we get
x=5
y=2
Plz mark brainliest
Answered by
0
may my answer is correct I am not sure
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