the sum of two digits of the two digit no.is 7 .If the number obtained by interchanging the digit is 27 more than the original no. find original no.
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Let the unit digit be x , then tens place digit will be 3−x
So, the given number = x+10(3−x)
= x+30−10x
= 30−9x
If digits are interchanged , then the number obtained = 10x+3−x
= 9x+3
According to question
9x+3 = 30−9x−9
⇒18x=18
⇒ x=1
So , 3−x =3−1=2
Hence the required number is 21
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