Question

The sum of two dogit number and number obtained by reversing the digits is 66 . If digit of number is differ by 2,find number

Answer 1

Answer:

Step-by-step explanation:

Answer:Number is 42.

Solution:

Let the two digits number is xy,this can be represented as 10x+y

on reversing the number the number become yx, now this can be represented as 10y+x

according to the question the sum of two digit number and the number reversing the digits is equal to 66

the digit of the number differ by 2,hence it can be represented algebraically

Now solve these two equations,here I am using Elimination method,add both equations

Hence number is 42.

it's reverse number is 24.

Verification:

42+24=66

Answer 2

Answer:

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