Question

The sum of two forces at a point is 16N. If the R is Normal to smaller force & has a value of 8N. Find two forces?

Answer 1

Answer:

The two forces are 6 and 10

Explanation:

Let the force of smaller magnitude be A and force of larger magnitude be B.

Here, it is clearly given that the resultant force is R perpendicular to the small force.

Hence, we can say that b is the hypotenuse.

Therefore,

b²=R²+A²

R²=b²-A²

R²=8²

R²=64..…...(1)

here, it is also given that

A+B=16

B=16-A........(2)

Now, by substituting (2) in (1)

we get,

(16-A)²-A²=64

256-32A+A²-A²=64

32A=256-64=192

A=192/32=6

hence, we get the result

B=16-A=16-6=10

Therefore,

The two forces are 6 and 10.