Question

The sum of two fractions is 5+3/9. If one of the fractions is 2+3/4 find the other fraction.
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Answer 1

Answer:

the answer is 35 Of your question

Answer 2

➤ Answer :-

${\tt \longrightarrow \bigg(2 + \dfrac{3}{4} \bigg) + \sf(x) \tt = \bigg(5 + \dfrac{3}{9} \bigg)}$

To find the value of 'x' in the following sum, first we should solve the brackets and then we should subtract the answer and the first value

${\tt \longrightarrow \bigg(2 + \dfrac{3}{4} \bigg) \: ; \: \bigg(5 + \dfrac{3}{9} \bigg)}$

${\tt \longrightarrow \bigg(\dfrac{2}{1} + \dfrac{3}{4} \bigg) \: ; \: \bigg(\dfrac{5}{1} + \dfrac{3}{9} \bigg)}$

Convert them into like fractions by taking the LCM of the denominators i.e, 1 and 4 and the other 1 and 9

LCM of 1 and 4 is 4.

LCM of 1 and 9 is 9.

${\tt \longrightarrow \bigg(\dfrac{2 \times 4}{1 \times 4} + \dfrac{3}{4} \bigg) \: ; \: \bigg(\dfrac{5 \times 9}{1 \times 9} + \dfrac{3}{9} \bigg)}$

${\tt \longrightarrow \bigg(\dfrac{8}{4} + \dfrac{3}{4} \bigg) \: ; \: \bigg(\dfrac{45}{9} + \dfrac{3}{9} \bigg)}$

${\tt \longrightarrow \bigg(\dfrac{8+3}{4} \bigg) \: ; \: \bigg(\dfrac{45+3}{9} \bigg)}$

${\tt \longrightarrow \bigg(\dfrac{11}{4} \bigg) \: ; \: \bigg(\dfrac{48}{9} \bigg)}$

Now,

Correct statement :-

${\tt \longrightarrow \dfrac{11}{4} + \sf (x) = \tt \dfrac{48}{9}}$

${\sf \longrightarrow (x) = \tt \dfrac{48}{9} - \dfrac{11}{4}}$

Convert them into like fractions by taking the LCM of the denominators i.e, 9 and 4

LCM of 9 and 4 is 36.

${\tt \longrightarrow \tt \dfrac{48 \times 4}{9 \times 4} - \dfrac{11 \times 9}{4 \times 9}}$

${\tt \longrightarrow \dfrac{192}{36} - \dfrac{99}{36}}$

${\tt \longrightarrow \dfrac{192 - 99}{36}}$

${\tt \longrightarrow \dfrac{93}{36} = \boxed{\tt 2 \dfrac{21}{36}}}$

$\Huge\therefore$ The other number is ${\tt 2 \dfrac{21}{36}}$

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More to know :-

• While adding or subtracting the fractions, if the given fractions are mixed fractions we should convert them into improper fractions by multiplying the denominator and whole number and then by adding the numerator.
• While adding or subtracting the fractions, if the given fractions are unlike fractions we should convert them into like fractions by taking the LCM of the denominators.
• While adding or subtracting the fractions, if the given fractions are like fractions we can solve them easily.