Question

the sum of two fractions is 7/8 and difference is 1/8.what are the fraction.

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Answer 1

Answer:

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Answer 2

Answer: $x=\frac{4}{8} , y=\frac{3}{8}-Ans$

Step-by-step explanation:

Let the two fractions be x,y

Let x≥y

Therefore x+y = $\frac{7}{8}$ ,x-y=$\frac{1}{8}$

Adding both equations

Therefore ,

$(x+y)+(x-y)=\frac{7}{8}+\frac{1}{8} \\x+y+x-y=\frac{8}{8} \\2x=\frac{8}{8} \\x=\frac{4}{8} -ANS\\\\since \\x+y=\frac{7}{8} \\y=\frac{7}{8} -x\\y=\frac{7}{8} -\frac{4}{8}=\frac{3}{8}-ANS\\\\x=\frac{4}{8} , y=\frac{3}{8}-Ans$