the sum of two given numbers is 40. if the smaller number is doubled, it becomes 14 more than the larger number. give the algebraic equation and find the solution graphically. please show the graph also. urgent!!!!
Answers
Answered by
0
Answer:
Let the larger number be x
and smaller number be y
As per the question, we have
x+y=40 ....(1)
and 2y=14+x ....(2)
Therefore, y=
2
14+x
....(3)
Substitute this value of y in equation (1), we get
x+
2
14+x
=40
⇒2x+14+x=80
⇒3x=80−14
⇒3x=66
⇒x=22
Put this value of x in equation (3),
y=
2
14+22
⇒y=18
therefore, the two numbers are 22 and 18.
Answered by
0
Answer:
therefore, the two numbers are 22 and 18
Step-by-step explanation:
Let the larger number be x
and smaller number be y
As per the question, we have
x+y=40 ....(1)
and 2y=14+x ....(2)
Therefore, y=
2
14+x
....(3)
Substitute this value of y in equation (1), we get
x+
2
14+x
=40
⇒2x+14+x=80
⇒3x=80−14
⇒3x=66
⇒x=22
Put this value of x in equation (3),
y=
2
14+22
⇒y=18
therefore, the two numbers are 22 and 18.
HOPE IT HELPS.
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