Question

The sum of two given numbers P and Q is 56. Their LCM and HCF is 96 and 8 respectively. Find P____________________________________________

Answer 1

Answer:

lcm×hcf = product of no

p×q= 96*8

now,

p+q=56 ...1

therefore p-q=√(p+q)^2-4pq

= √56^2-4*96*8

p-q=8 ......2

now

adding both equation

p=32

so, q=24

ans.....