Question

The+sum+of+two+inegers+is+(-11)+and+their+product+is+-80.what+are+the+two+integers?

Answer 1

Answer:

Two integers are 5 and -16

Step-by-step explanation:

Given that,

Sum of the two integers  = -11

Product of the two integers = + 80

To Find :

The value of the two integers.

Let x and y be the integers,then

According to Question,

x + y = -11 ............(1)

xy = - 80 ............(2)

From equation (2), x = -80/y

Substitute x = -80/y in equation(1),

x + y = -11

-80/y +y = -11

$\frac{-80 +y^{2} }{y}$ = -11

$-80+ y^{2}$ = -11y

$y^{2} +11y - 80$ = y^2-16y+5y-80 = y(y-16)+5(y-16)

y-16 = 0 : y + 5 = 0

y = -16 or -5

Therefore,x = -80/-5 = 16 or -80/-16 = 5

Two integers are, x + y = 5 - 16 = -11 ; (5)(-16) = -80

Two integers are 5 and -16

Hope you understand :)

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