Question

The sum of two integer is -11 and their product is -80. What are the integers

Answer 1

I hope it's helpful

mark me as a Brainlist

Answer 2

Answer:

let one no. be x and other be y

ACC to question.

$x + y = - 11 \: - - - - 1 \\ xy = - 80 - - - - - 2 \\ \\ \\ from \: eq \: 1 \: and \: 2 \\ \frac{ - 80}{y} + y = - 11 \\ - 80 + {y}^{2} = - 11y \\ {y}^{2} + 11y - 80 = 0 \\ {y}^{2} + 16y - 5y - 80 = 0 \\ y(y + 16) - 5(y + 16) = 0 \\ (y - 5)(y + 16) = 0 \\ so \: y = 5 \: or \: y = - 16 \\ now \: put \: the \: value \: of \: y \: in \: eq. \: 1 \\ \\ \\ when \: y = 5 \\ \\ x + 5 = - 11 \\ x = - 16 \\ \\ when \: x = - 16 \\ x - 16 = - 11 \\ x = 5$

HOPE IT HELPS.....

PLEASE MARK ME AS BRAINLIEST ANSWER....