the sum of two integer is -11 and their product is -80.what are the two integer
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Answered by
15
Let the integers be a and b
a + b = - 11 ⇒ b = - (11 + a)
ab = - 80
- a (11 + a) = - 80
a (11 + a) = 80
We know that 16 x 5 = 80
So, a = 5
b = - (11 + a) = - (11+5) = - 16
So, 5 and - 16 are the integers required
a + b = - 11 ⇒ b = - (11 + a)
ab = - 80
- a (11 + a) = - 80
a (11 + a) = 80
We know that 16 x 5 = 80
So, a = 5
b = - (11 + a) = - (11+5) = - 16
So, 5 and - 16 are the integers required
Answered by
1
Answer:
5 and -16
Step-by-step explanation:
Let the integers be a and b
a + b = - 11 ⇒ b = - (11 + a)
ab = - 80
- a (11 + a) = - 80
a (11 + a) = 80
We know that 16 x 5 = 80
So, a = 5
b = - (11 + a) = - (11+5) = - 16
So, 5 and - 16 are the integers required
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