The sum of two integer is _11 and their product is _80 what are the values of two integer ?
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a+b=11
ab=80 , a=80/b
a=11-b
80/b=11-b
80=11b-b^2
11b-b^2-80
now by middle term splitting the answer is there
ab=80 , a=80/b
a=11-b
80/b=11-b
80=11b-b^2
11b-b^2-80
now by middle term splitting the answer is there
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