Question

the sum of two integers is -11 and their product is -80 . what are the two integers.​

Answer 1

Answer:

5,-16

Step-by-step explanation:

let the two integers be x,y

the sum of two integers- x+y=-11

their product- (x) (y)=-80

x+y=-11

x=-11-y (equation 1)

(-11-y) (y)=-80

(-11y) (-y^2)=-80

y^2+11y-80=0. (change the signs)

b^2-4ac

121+4*80

121+320

441

x=-b-+√b^2-4ac/2a

=-11+-21/2

=-11+21/2. =-11-21/2

=10/2. =-32/2

=5. =-16

therefore5,-16 are the two integers.